Re^3: Pass array, then clear

I did not suspect that the subroutine made a copy of the memory address

It doesn't. You do, with the my($data) = @_; snippet. If you directly manipulate the argument, it works as you expect:

sub clear_it {
    $_[0] = [];
}
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Because you're then working on the original reference, not on the copy you made.

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Re^4: Pass array, then clear by Anonymous Monk on Jan 16, 2018 at 18:37 UTC
Thank you, I did not realize that!	[reply]
Re^4: Pass array, then clear by Anonymous Monk on Jan 16, 2018 at 20:36 UTC
This reply really brings it home for me. Light coming on strongly (or is it just the flames of the reference burnage?). I now see the error of my ways.	[reply]