in reply to Regular Expression Question

Please tell us exactly what you want to do? If your trying to pull the information out of that output try using a regex.

Something like this,
m/(\/.+) +(\d) +(\d) +(\d+) +(\d)% +(.+)/

You would then be able to test $5 to see if it is over 80.

NOTE My regex is not in anyway the best and I'm not even sure if that would work. But I hope you get the idea. If you want to know more read up on regex. UPDATE My post was outdated before I even post it :)

The Price of Freedom is Eternal Vigilance

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Re: Re: Regular Expression Question
by larryk (Friar) on Mar 27, 2001 at 22:00 UTC
    you are right to suspect that this would not work - the single \d as opposed to \d+ before the % would mean that the regex would fail to match unless the % was between 0 and 9.

    what I expect you are looking for is for(<>) { /(\d+)%/; print if $1 >= 88 }

      Thanks larry. Typo on my part. It was supposed to be (\d+)%

      The Price of Freedom is Eternal Vigilance