Re: short method to print age.

This mimics what you do.

print "Alex children are \n\n        "
, join("\nand     ", map $_->{age}, reverse @{$alex{children}})
, "years old\n";
[download]

Obviously the reverse isn't necessary unless you really want it.

Caution: Contents may have been coded under pressure.

Comment on Re: short method to print age. Download Code

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Re^2: short method to print age. by zouz (Initiate) on Mar 05, 2009 at 19:42 UTC
Thank you all for the answers you guys offered. i think i will end up using this code. `#!/usr/bin/perl use warnings; %alex = ( 'name' => 'Alex', 'age' => '45'); %john = ( 'name' => 'John', 'age' => '20'); %chaddy = ( 'name' => 'Chady', 'age' => '16'); @children = (\%john, \%chaddy); $alex{'children'} = \@children; print "Alex children are \n " , join("\nand ", map $_->{age}, reverse @{$alex{children}}) , "\tyears old\n"; print "Alex is $alex{age} himself\n";` [download] instead of the one i mentioned above. much easier to understand i guess,thx Roy and thank you all once again.	[reply] [d/l]

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Re^2: short method to print age.
by zouz (Initiate) on Mar 05, 2009 at 19:42 UTC

#!/usr/bin/perl
use warnings;

%alex = (              
    'name' => 'Alex',
    'age'  => '45');
%john = (              
    'name' => 'John',
    'age'  => '20');
%chaddy = (            
    'name' => 'Chady',
    'age'  => '16');

@children = (\%john, \%chaddy);
$alex{'children'} = \@children;

print "Alex children are \n        "
, join("\nand     ", map $_->{age}, reverse @{$alex{children}})
, "\tyears old\n";
print   "Alex is $alex{age} himself\n";
[download]

[reply]
[d/l]

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