http://qs1969.pair.com?node_id=291993


in reply to Fun with one keyword

As with the competition over here, i wondered if it could be done without any \w characters. Well, i cheated and spliced the idea above from Abigail (using *nix comands via backticks) with the standard way of doing it (bit xor'ing characters) and came up with the following:
$,=('%'^'@').('#'^'@').('('^'@').('/'^'@').$".('*'^'`').('('^']').( '('^'[').('('^'\\').$".('!'^'@').('.'^'@').('/'^'@').('('^'\\').('(' ^'@').('%'^'@').(')'^'[').$".('+'^'{').('%'^'@').(')'^'[').(','^'@') .$".('('^'@').('!'^'@').('#'^'@').('+'^'@').('%'^'@').(')'^'[').', > / +' .('$'^'@').('%'^'@').('('^'^').'/'.('('^'\\').('('^'\\').('"'^'['),`$, +`
not very interesting, but it gets the job done...

jynx

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Re: Re: Fun with one keyword
by mtve (Deacon) on Sep 17, 2003 at 09:05 UTC