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Adding 2 + 2

by merlyn (Sage)
on Sep 11, 2000 at 06:22 UTC ( [id://31832]=CUFP: print w/replies, xml ) Need Help??

This snippet was created accidentally with an empty title, while I was scanning for other snippets to up-vote. And it was created with an empty subject, requiring me to "view source" to pick out the node number, which I then next sent to myself as a message in the chatterbox as /tell merlyn [id://31832|this one]. I then followed the link, and was able to press the "edit this" link from there, which I am now typing at.

So, unable to think of something useful to put here (except the path by which I got to this node), I now give you...
How to add 2 + 2 with Perl

$result = 2 + 2; print "the answer is $result\n";

Replies are listed 'Best First'.
Re: Adding 2 + 2
by I0 (Priest) on Dec 31, 2000 at 21:36 UTC
    package Conway; use overload '+' => \&Add, '-' => \&Sub, '*' => \&Mul, '>=' => \&Geq, '<=' => \&Leq, '==' => \&eql, '<=>' => \&Cmp, 'neg' => \&Neg, '++' => \&Succ, '""' => \&Name, '0+' => \&Value, '=' => \&Copy, bool => sub{my $x = shift; return !Eql($x,$zero)}, ; sub Geq{ my($x,$y) = @_; my @xL = @{$x->[0]}; my @xR = @{$x->[1]}; my @yL = @{$y->[0]}; my @yR = @{$y->[1]}; return !(grep{Leq($_,$y)}@xR) && !(grep{Leq($x,$_)}@yL); } sub Leq{ my($x,$y) = @_; return Geq($y,$x); } sub Eql{ my($x,$y) = @_; return Geq($x,$y) && Geq($y,$x) } sub Gtr{ my($x,$y) = @_; return Geq($x,$y) && !Geq($y,$x); } sub Cmp{ my($x,$y) = @_; my $g = Geq($x,$y); my $l = Leq($x,$y); return undef unless $g || $l; return 0 if $g && $l; return 1 if $g && !$l; return -1 if !$g && $l } sub Neg{ my $x = shift; my @xL = @{$x->[0]}; my @xR = @{$x->[1]}; return bless [ [map{Neg($_)}@xR], [map{Neg($_)}@xL] ]; } sub Add{ my($x,$y) = @_; my @xL = @{$x->[0]}; my @xR = @{$x->[1]}; my @yL = @{$y->[0]}; my @yR = @{$y->[1]}; bless[ [ (map{Add($_,$y)} @xL), (map{Add($x,$_)} @yL), ], [ (map{Add($_,$y)} @xR), (map{Add($x,$_)} @yR), ] ]; } sub Sub{ my($x,$y) = @_; Add($x,Neg($y)); } sub dmap(&$$){ my $f = shift; my @a = @{shift @_}; my @b = @{shift @_}; map{ local $a = $_; map{ local $b=$_; &$f } @b; } @a; } sub Mul{ my($x,$y) = @_; my @xL = @{$x->[0]}; my @xR = @{$x->[1]}; my @yL = @{$y->[0]}; my @yR = @{$y->[1]}; bless [ [ (dmap{Sub(Add(Mul($a,$y),Mul($x,$b)),Mul($a,$b))} \@xL,\@yL), (dmap{Sub(Add(Mul($a,$y),Mul($x,$b)),Mul($a,$b))} \@xR,\@yR), ], [ (dmap{Sub(Add(Mul($a,$y),Mul($x,$b)),Mul($a,$b))} \@xL,\@yR), (dmap{Sub(Add(Mul($a,$y),Mul($x,$b)),Mul($a,$b))} \@xR,\@yL), ] ] } sub L{ my $x = shift; return @{$x->[0]}; }; sub R{ my $x = shift; return @{$x->[1]}; } sub normalize{ my($x,$y) = @_; my @xL = map{normalize($_)} @{$x->[0]}; my @xR = map{normalize($_)} @{$x->[1]}; while( @xR > 1 ){ if( Geq(@xR[0],@xR[-1]) ){ shift @xR; }elsif( Geq(@xR[-1],@xR[0]) ){ pop @xR; }else{ warn "NaN"; last; } } while( @xL > 1 ){ if( Geq(@xL[0],@xL[-1]) ){ pop @xL; }elsif( Geq(@xL[-1],@xL[0]) ){ shift @xL; }else{ warn "NaN"; last; } } bless [[@xL],[@xR]]; } sub Succ{ my $x = shift; bless [[$x],[]]; } sub Copy{ my $x = shift; normalize($x); } sub new{ my $class = shift; my ($L, $R) = @_; my $n = [$L,$R]; bless $n,$class; return $n; } sub Name{ my $x = shift; # return 0 if Eql($x,$zero); my @xL = @{$x->[0]}; my @xR = @{$x->[1]}; my $L=join",",map{Name($_)} @xL; my $R=join",",map{Name($_)} @xR; return "{$L|$R}"; } sub Value{ my $x = normalize(shift); my $g = Geq($x,$zero); my $l = Leq($x,$zero); return NaN unless $g || $l; return 0 if $g && $l; return -Value(Neg($x)) if $l && !$g; return 1+Value(Sub($x,$one) ) if( Geq($x,$one)); return Value( Mul($x,$two) )/2; } $zero = new Conway [],[]; $one = $zero->Succ; $two = $one+$one; #print "$one+$one=$two\n"; #print Value($one),"+",Value($one),"=",Value($two),"\n"; $two = normalize($two); #print "$one+$one=$two\n"; #print Value($one),"+",Value($one),"=",Value($two),"\n"; print "$two+$two=",$two+$two,"\n"; print Value($two),"+",Value($two),"=",Value($two+$two),"\n"; #print Value(Mul($two,$two)),"\n"; #print Value([[$zero],[$one]]),"\n"; 1;
      Anyone who doesn't understand this post should go read about Conway's surreal numbers. This is very, very cool! :-)

      UPDATE
      Thanks to coreolyn the link should now work.

RE: Adding 2 + 2
by and (Pilgrim) on Sep 12, 2000 at 01:11 UTC
    One lunch I was complaining about how or and die get all of the good work and some of my bit-twiddling coworkers said that they hardly ever have anything to do. We went out for drinks later and they tried to teach me what they know about integers. I find it very hard to understand but I think I figured out how to do 2+2.

    sub add { my( $a, $b, $bit, $cary, $sum ) = ( @{$_[0]}, 1, 0, 0 ); $sum |= $bit if 1 & ( $a ^ $b ^ $cary ); $cary = 1 & ( $a & $b | ( $cary & ($a|$b) ) ); return $a | $b ? [$a>>1,$b>>1,$bit<<1,$cary,$sum] : $sum; } my @args = map {0+$_} (@ARGV,2,2)[0,1]; my $acc = add( [@args] ); $acc = add($acc) while ref $acc; print "add[@args] = $acc\n";
RE: Adding 2 + 2
by KM (Priest) on Sep 11, 2000 at 19:01 UTC
    Ok, this is fun :)

    perl -MFcntl=:flock -e 'print 2+LOCK_EX'

    Or (cheap way)

    perl -wle 'print $^W*2**$^W*2'

    Or (Only works if you follow the directions ;-)

    #!/usr/bin/perl -w use strict; print "Pick an integer between 1 and 3\n"; my $num = <STDIN>; print "Pick another integer between 1 and 3\n"; $num += <STDIN>; print "The sum is " . $num;

    Or

    perl -wle '%h = map {(qq{sum}) => $h{'sum'}+=$_ } qw/2 2/; print $h{s +um}'

    Or (a long version of the above one liner)

    #!/usr/bin/perl -w use strict; my %foo; %foo = map {('sum') => $foo{'sum'}+=$_ } qw/2 2/; print $foo{sum};

    More later if I have time.

    Cheers,
    KM

      I follow the directions, but it tells me that the sum is 3. Did you mean to write directions that do not allow 1.5 as input?
        Haha.. I made the directions more clear.

        Cheers,
        KM

      perl -wle 'print $^W*2**$^W*2'
      That's not 2 + 2, thats 2 squared.
      (Ok, I know... the answer is the same... but the route is different.)
        Well, speaking as a engineer by training, the program meets spec... where's the problem? <G>

        If you wanted flexibility and easy upgrades, you should have made sure that was part of the original program spec.

        Ozymandias pries tongue from cheek...

        - email Ozymandias
        Uh, I thought 2 squared was just a shorthand for 2 + 2, er, or inherently linked or something. Sure, it a ... what's that word, pathological? case but ...

        a

      *bends down on knee*
      Will you marry me? ;)
RE: Adding 2 + 2
by t0mas (Priest) on Sep 11, 2000 at 10:13 UTC
    Q: How many ways are there?
    A: TMTOWTDI
    $_="2+2"; print $_."=".eval;


    /brother t0mas
      How many ways are there?

      I'm wondering about the number of solutions as a function of program length. Does the number of solutions / number of possible programs increase or decrease as the length grows?

RE: Adding 2 + 2
by Adam (Vicar) on Sep 11, 2000 at 08:23 UTC
(ar0n) RE: Adding 2 + 2
by ar0n (Priest) on Sep 11, 2000 at 11:25 UTC
    #!/usr/bin/perl -w use strict; my $i = 3; my $j = $i-1; my $n = $i & $j; print "$n + $n = ", $n + $n;

    -- ar0n, i broke my 'two' key :-(

(jcwren) RE: Adding 2 + 2
by jcwren (Prior) on Sep 11, 2000 at 07:38 UTC
    #!/usr/local/bin/perl -w use strict; { my $addy = "2 + 2"; print "Adding $addy = ", eval ($addy), "\n"; }
    It's late, it's time for bed, and I couldn't make Inline work in 30 seconds, so I cheated...

    --Chris

    e-mail jcwren
RE: Adding 2 + 2
by Adam (Vicar) on Sep 11, 2000 at 21:00 UTC
    Ok, I have a few more. First, the one I posted last night followed by several new ones. (Including one that uses no digits)
    perl -we "$,=2+2=>print('The result is ',$/)" perl -we "1while(2+2>++$.);print qq;The result is $.$/;" perl -we "tie $sum,'_',4;print 'The result is ',$sum,$/;sub _::TIESCAL +AR{bless[pop],'_'}sub _::FETCH{$_[0][0]=2+2}" perl -we "my $two=$^W+!''; print 'The result is ',$two + $two,$/" perl -we "print reverse $/,eval(join'+',(2)x2),'The result is '" perl -we "$_=qq/The result is 2+2\n/=>y/2\+2/4/s,print"
    I can only get away with the last one because Ozymandias says I can.
RE: Adding 2 + 2
by myocom (Deacon) on Sep 12, 2000 at 00:53 UTC
    print 4;

    Hey, it meets spec too!

(jcwren) RE: Adding 2 + 2
by jcwren (Prior) on Sep 11, 2000 at 21:26 UTC
    #!/usr/local/bin/perl -w use strict; use Lingua::EN::Numbers qw(American); { my $v++; my $t=new Lingua::EN::Numbers(++$v); my $f=new Lingua::EN::Numbers($v*$v); print sprintf "Adding %s + %s = %s\n",$t->get_string,$t->get_string +,$f->get_string; }
    --Chris

    e-mail jcwren
RE: Adding 2 + 2
by jeorgen (Pilgrim) on Sep 11, 2000 at 19:49 UTC
    my $four; my @array = split "", (2 x 2); sub the { my $four = shift; return "two plus two is: $four"} sub answer { print shift} sub result { return $four} foreach my $two (@array) { $four += $two } answer the result;

    /jeorgen

Re: Adding 2 + 2
by mkmcconn (Chaplain) on Feb 11, 2001 at 03:51 UTC
    2+2 illustrates some interesting behavior.
    1. ++$_ && $_++ && print eval() + eval();
    2. $_++; print eval() + eval() unless ( $_ + 1 == $_++ );
    3. for (2..2){$_ = $_ + $_ and print;}
    4. $a = 2; print "$a + $a = ", $$b + $$b; BEGIN{ $b = \$a }
    5. my $num = 2; $num =~ s/(2)/$1 + $1/gxe; print $num;

    mkmcconn
(crazyinsomniac) RE: Adding 2 + 2
by crazyinsomniac (Prior) on Sep 11, 2000 at 06:38 UTC
    print "Adding 2 + 2 =".(2+2)."\n";

    "cRaZy is co01, but sometimes cRaZy is cRaZy".
                                                          - crazyinsomniac

Re: Adding 2 + 2
by I0 (Priest) on Dec 30, 2000 at 18:33 UTC
    sub S{ return [shift]; } sub P{ return (shift)->[0]; } sub add{ my($x,$y) = @_; return $x unless $y; return add(S($x),P($y)); } sub arabic{ my $x = shift; return 0 unless $x; return 1+arabic(P($x)); } $y=$x = S S; print arabic($x),"+",arabic($y),"=",arabic(add($x,$y)),"\n";
RE: Adding 2 + 2
by BastardOperator (Monk) on Sep 11, 2000 at 17:11 UTC
    Only on PerlMonks....only here would you find this much attention given to adding 2 + 2 ;). I got a real chuckle out of this
Re: Adding 2 + 2 (stack machine)
by ikegami (Patriarch) on Jan 30, 2007 at 18:10 UTC
    Stack machine!
    my @stack; my $acc = 0; sub PUSH() { push(@stack, $acc); } sub POP() { pop(@stack); } sub INC() { $acc++; } sub ADD() { $acc += POP; } INC; INC; PUSH; ADD; print($acc, "\n");
      The parent assumed the accumulator was initially zero. That's not likely in a real-life scenario, so this removes the assumption:
      my @stack; my $acc = rand; sub PUSH() { push(@stack, $acc); } sub POP() { pop(@stack); } sub INC() { $acc++; } sub ADD() { $acc += POP; } sub SUB() { $acc -= POP; } PUSH; SUB; INC; INC; PUSH; ADD; print("$acc\n");
RE: Adding 2 + 2
by mirod (Canon) on Sep 11, 2000 at 21:43 UTC
    unless( my $pid= open( STDOUT, "|-")) { while( <STDIN>) { chomp; s/(.*)/qq{$1}. "= " . eval($1) ."\n"/e; print; } exit; } print "2+2\n";
(jcwren) RE: Adding 2 + 2
by jcwren (Prior) on Sep 11, 2000 at 21:44 UTC
    The Doesn't completely use Perl solution. Last one, I promise.
    #!/usr/local/bin/perl -w use strict; { my $v=2; print "Adding $v + $v = ", `echo $v $v + p | dc`; }
    (This should even work on Win32 with the cygwin stuff)

    --Chris

    e-mail jcwren
RE: Adding 2 + 2
by d4vis (Chaplain) on Sep 12, 2000 at 02:32 UTC
    @list=(1,2,3); if ($list[1] eq '2' && $list[2]++ eq '3') { print "The answer is $list[2]\n"; } else { print "Insufficiently large value of 2\n"; }


    ~d4vis
    #!/usr/bin/fnord
RE: Adding 2 + 2
by rodry (Beadle) on Sep 11, 2000 at 10:09 UTC
    And I though I had a lot of free time.
Re: Adding 2 + 2
by mr_mischief (Monsignor) on Dec 21, 2001 at 14:21 UTC
    I didn't notice anyone using Roman numerals. I tested the applicable subroutine with lots of values, since I wrote it for this and hadn't used it before. If there are any bugs with it other than the design decision documented, please let me know. This might actually sneak into a project since I spent a good half hour designing, coding, testing, and commenting it.

    Chris
      A very creative solution :)
      Be sure to check out Roman if you didn't know it already. It can convert roman numbers both ways, and checks if your roman input is valid.

      use Roman; $calc = "II + II"; $calc =~ s/([MDCLXVI]+)/isroman($1) ? arabic($1) : $1/; print eval $calc;

      2;0 juerd@ouranos:~$ perl -e'undef christmas' Segmentation fault 2;139 juerd@ouranos:~$

        Thanks for the review and the suggestion.

        I knew Roman was available, but it didn't feel right to use it for this. I felt it was more in the spirit of the thread to go overboard and develop the needed tools specifically for the node. I'm actually a bit surprised it took someone posting a hand-crafted Roman to Arabic numeral conversion before someone gave an example using the module. It was one of the first twists on the problem that popped into my deranged mind.
        I didn't know about the contest until just now. Thanks for asking, though. I'm enjoying looking at the site.


        Christopher E. Stith
Re: Adding 2 + 2
by ikegami (Patriarch) on Jul 22, 2005 at 15:47 UTC
    $lterm = 2; # lterm = 2 $rterm = 2; # rterm = 2 $#add = $lterm; pop(@add); # add = lterm push(@acc, @add); # acc += add $#add = $rterm; pop(@add); # add = rterm push(@acc, @add); # acc += add push(@acc, 1); $sum = $#acc; # sum = acc print("$sum\n");

    It must be fast, since the addition is done by push, which is written in C! ;)

Re: Adding 2 + 2
by mrborisguy (Hermit) on Jul 24, 2005 at 02:21 UTC
    use Language::Haskell; print Language::Haskell->new->eval('foldr (+) 0 [2,2]');

    (Hey, I saw somebody do it with C, so I can do it in Haskell)

    use Language::Functional qw(foldr); print foldr { $_[0] + $_[1] } 0, [2,2];

        -Bryan

Re: Adding 2 + 2
by arkturuz (Curate) on Jan 31, 2007 at 09:44 UTC
    And now for something completely different:
    say 2+2;

    P.S. I've been waiting so long to put those Monty Pythons' words on the stage, I now I finally got it :-)

Re: Adding 2 + 2 (Church numerals)
by blokhead (Monsignor) on Jan 30, 2007 at 18:43 UTC
    Lambda calculus! But it doesn't have integers (or any data types for that matter), you say? Sure it does, it has Church numerals!
    my $two = sub { my($f,$x) = @_; $f->($f->($x)); }; sub add { my($m,$n) = @_; sub { my($f,$x) = @_; $m->($f, $n->($f, $x)) }; } sub decode { my($n) = @_; $n->( sub{$_[0]+1}, 0 ); } print decode( add($two, $two) ), $/;
    Yeah, at some point we have to convert the Church numeral to something that Perl can print.. but you get the idea.

    blokhead

RE: Adding 2 + 2
by Anonymous Monk on Sep 26, 2000 at 02:00 UTC
    (undef$a)and(undef$b)or++$a;while( $a!=2){$a++if($b);$b++if(not$b);} $b++?$d=$a.'+'.$b.'=':die;map{$c+= $_;}($a,$b);$_=$d.$c."\n";print;
Re: Adding 2 + 2
by roboticus (Chancellor) on Jan 31, 2007 at 03:53 UTC
    At first, I tried this simple recursive algorithm:

    #!/usr/bin/perl -w use strict; use warnings; sub add { my ($first, @rest) = @_; if (!defined $first) { 0; } else { die "operand may not be negative!" unless $first >= 0; if ($first == 0) { add(@rest); } else { 1 + add($first-1, @rest); } } } sub print_add { print join(" + ", @_), " = ", add(@_), "\n"; } print_add 2,2; print_add 2,2,2; print_add 4,8,12;
    which yields the results:

    root@swill ~/PerlMonks $ ./adder_1.pl 2 + 2 = 4 2 + 2 + 2 = 6 4 + 8 + 12 = 24
    But I then realized that the algorithm used is essentially tail-recursive. Thus, it can be optimized! Converting the add routine from tail-recursive form to an iterative form yields:

    sub add { my $accumulator = 0; for my $op (@_) { for my $i (1 .. $op) { $accumulator = $accumulator+1; } } $accumulator; }
    Now all that remained is to verify that the conversion was worthwhile:

    #!/usr/bin/perl -w use strict; use warnings; use Benchmark qw(timethese cmpthese); sub add_rec { my ($first, @rest) = @_; if (!defined $first) { 0; } else { die "operand may not be negative!" unless $first >= 0; if ($first == 0) { add_rec(@rest); } else { 1 + add_rec($first-1, @rest); } } } sub add_iter { my $accumulator = 0; for my $op (@_) { for my $i (1 .. $op) { $accumulator = $accumulator+1; } } $accumulator; } cmpthese(100000, { 'Recursive' => sub { 2 == add_rec(2,2); }, 'Iterative' => sub { 2 == add_iter(2,2); } });
    Running the benchmarking program shows:

    $ ./adder_bench.pl Rate Recursive Iterative Recursive 79051/s -- -48% Iterative 152207/s 93% --
    Success!

    The iterative version is *much* faster than the recursive one. I'm certain that this new algorithm for adding should be used in all future programs, as the iterative version is better both in speed (it's nearly twice as fast!) as well as consuming far less memory than it's recursive counterpart when adding large numbers.

    --roboticus

    Awaiting his Turing prize for this valuable discovery...

Re: Adding 2 + 2
by GrandFather (Saint) on Jan 29, 2007 at 19:57 UTC

    Look ma, no numbers:

    $|++; my $two = $| + $|; print "$two + $two = ", $two + $two;

    Prints:

    2 + 2 = 4

    DWIM is Perl's answer to Gödel

      That's really an interesting way of getting 1, not 2. Other interesting ways to get 1:

      my $one = !@!; my $one = !!$]; my $one = /.*/; # Side-effect: Changes $1, etc my $one = $$/$$; my $one = ()=$$; my $one = @{[$$]}; my $one = 'a'^'P'; # Character set specific. my $one = ord('b')-ord('a'); # Character set specific.

      And 2:

      my $two = $one+$one; my $two = $one<<$one; my $two = ()=qw(a a); my $two = @{[ qw(a a) ]}; my $two = ()=/(.*)(.*)/; # Side-effect: Changes $1, etc my $two = 'a'^'S'; # Character set specific. my $two = ord('c')-ord('a'); # Character set specific.

      None of these have side effects unless otherwise noted.
      All of these run under use strict;.
      All of these run silently under use warnings;.

        More (although not as neat):

        my $one = !$|; my $one = cos; # Given that $_ == 0. my $one = cos $|; my $one = cos atan2 $|, cos; my $one = sin atan2 sin, $|; my $one = length $/; # Note: possibly 2 under Windows or DOS. my $one = length $"; my $one = length $;; my $one = length $^L; my $one = $^T/$^T; my $one = @ARGV >= 0; my $one = grep //, ($_); my $one = !undef; # Note: the following may be Unix-only. Will not work if run as root, # as root's UID and GID are (always?) zero. my $one = $</$<; # User ID. my $one = $>/$>; # Effective user ID. my $one = $(/$(; # (Space-separated list of) group ID(s). my $one = $)/$); # (Space-separated list of) effective group ID(s +).

        Ways to get 2:

        my $two = length $:; my $two = $^F; # Note: system-dependent.

        --
        print "Just Another Perl Adept\n";

Re: Adding 2 + 2
by Errto (Vicar) on Jul 24, 2005 at 05:54 UTC
    A simple one that didn't make it in yet:
    print "2 + 2 = ${ \(2 + 2) }\n";
Re: Adding 2 + 2
by jdporter (Paladin) on Jan 30, 2007 at 19:27 UTC
    print map { /....(.)/ and $++$+ } "@{[0..9]}";

    my @c = ( my @a = each %ENV, my @b = each %SIG ); print @a . " + " . @b . " = " . @c . "\n";
    A word spoken in Mind will reach its own level, in the objective world, by its own weight
Re: Adding 2 + 2
by Anonymous Monk on Jul 24, 2005 at 05:15 UTC
    I don't know about 2+2, but I think 1+1=2 has been proven.
Re: Adding 2 + 2
by ciderpunx (Vicar) on Mar 04, 2007 at 14:29 UTC
Re: Adding 2 + 2
by webfiend (Vicar) on Feb 19, 2007 at 23:42 UTC

    Yet another look at it...

    #!/usr/bin/perl use warnings; use strict; use LWP::Simple; use HTML::Parser; # 'print' URL to save a smidge of bandwidth my $url = "http://perlmonks.org/?displaytype=print;node_id=31832"; if (my $page = get($url)) { my $parser = HTML::Parser->new( api_version => 3 ); $parser->handler( start => sub { return if shift ne 'title'; my $self = shift; $self->handler( text => sub { my $title = shift; # Only ready for 4-function math with integers if ($title =~ m#((\d+) (\+) (\d+))#) { print "$1 = ", eval("$2 $3 $4"), "\n"; } }, 'dtext' ); $self->handler( end => sub { shift->eof if shift eq 'title' ; }, 'tagname,self' ); }, 'tagname,self' ); $parser->parse($page); } else { print "Unable to fetch '$url' for some reason.\n"; }

    I chose to leave the database layer out of it this time.

Re: Adding 2 + 2
by shmem (Chancellor) on Jan 30, 2007 at 16:49 UTC
    $result = 2 + 2; print "the answer is $result\n";

    Er.. really? global $result? You don't need that variable:

    print "the answer is @{[2+2]}\n";

    Works under strict and warnings.

    --shmem

    _($_=" "x(1<<5)."?\n".q·/)Oo.  G°\        /
                                  /\_¯/(q    /
    ----------------------------  \__(m.====·.(_("always off the crowd"))."·
    ");sub _{s./.($e="'Itrs `mnsgdq Gdbj O`qkdq")=~y/"-y/#-z/;$e.e && print}

      It often strikes me as a little strange (or unfortunate) to use array ref/deref for this. The scalar version is only one character longer:

      print "the answer is ${\(2+2)}\n";
      A word spoken in Mind will reach its own level, in the objective world, by its own weight
        The scalar version is only one character longer
        golfer habits...

        --shmem
        But I might be parling heck.

        _($_=" "x(1<<5)."?\n".q·/)Oo.  G°\        /
                                      /\_¯/(q    /
        ----------------------------  \__(m.====·.(_("always off the crowd"))."·
        ");sub _{s./.($e="'Itrs `mnsgdq Gdbj O`qkdq")=~y/"-y/#-z/;$e.e && print}
Re: Adding 2 + 2
by tobyink (Canon) on May 24, 2012 at 08:15 UTC

    This one appears to suffer from an off-by-one bug...

    use Modern::Perl; use List::Util qw(first); use LWP::Simple qw(get); say for first {/^2\+2/} split m{\r?\n|\r}, get q{http://gutenberg.net.au/ebooks01/0100021.txt}

    (And monks outside of the Australian branch of the monastery need to be aware of potential copyright issues.)

    perl -E'sub Monkey::do{say$_,for@_,do{($monkey=[caller(0)]->[3])=~s{::}{ }and$monkey}}"Monkey say"->Monkey::do'

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