Couldn't $value = $value - 1; be written like this?:

$value -= 1;          # or
$value--   ;          # since its just -1
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- Jim

Yeah, they could.
I think this example is trying to limit itself to the syntax of the do/while loop, though. So it can be fully understood on its own. Using the 'minimalist' decrement operators might distract someone new to the language.

ok.. the code is bad. That situations cause problems to novices

$value=5 <------ ok that is the problem it does not have ;
do{
  print "$value\n";
  $value=$value-1;
} while($value>10);
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ok the correct code is

$value=5; # now have ;
do{
  print "$value\n";
  $value=$value-1;
} while($value>10);
[download]

have a fun

20041024 Edit by ysth: change p tags to code

Actually, I think the problem is larger than that.
shouldn't it be:

$value = 15;  # 15, not 5. 5 doesn't make sense if we're not increment
+ing.

do {
    print "$value\n";
    $value = $value - 1;
} while($value > 10);
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jdporter fixed formatting

The point was that the test happens at the end, so the loop executes once even if the value starts out < 10.

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Caution: Contents may have been coded under pressure.

do{ ... } while $foo; isn't a loop, it's a block with a postfixed while, so you need to label it to re-do it.

@_=qw; ask f00li5h to appear and remain for a moment of pretend better than a lifetime;;s;;@_[map hex,split'',B204316D8C2A4516DE];;y/05/os/&print;

sum = 0; for (x = 1; x <= 5; x++) { printf("%d", x); sum = sum + x; printf("The sum is %d", sum); }