Wow, how can
pairwise tell where the end of 1st array is? There was always the
problem feature that regardless whether you write
my @array1 = (3,4,6,5,8);
my @array2 = (2,2,4,5,1);
or
my @array1 = (3,4,6,5,8,2,2,4);
my @array2 = (5,1);
using it with coma always results in flattened list:
@array1,@array2
is equivalent to
(3,4,6,5,8,2,2,4,5,1)
and yet
pairwise deals with it:
c:\>perl -le "use List::MoreUtils qw/pairwise/; @a=(1..5);@b=(11..15);
+ print for pairwise {$a+$b} @a, @b"
12
14
16
18
20
c:\>perl -le "use List::MoreUtils qw/pairwise/; @a=(1..5, 11,12);@b=(1
+3..15); print for pairwise {$a+$b} @a, @b"
14
16
18
4
5
11
12
