Re: $1 not "freezing" in an addition

Does it work better if you "unreverse" the if condition?

if(s/\(#:(\d+)\)/#/) { 
    return $1 + distance($_);
}
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As I don't have the whole code, it's a bit difficult to test. And it's just a hunch.

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Re^2: $1 not "freezing" in an addition by grondilu (Friar) on Dec 14, 2012 at 12:42 UTC
Nope. (It was actually initially written as such, anyway)	[reply]


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