Re: Checking whether a $var is a number

If you use a value as a number, it is a number.

A string that can't be parsed as a number at all will be zero. So, how about something like this:

if ($x==0 && substr($x,0,1) ne '0') {
   # deal with non-number
   }
else {
   # deal with number
   }
[download]

In a real application, you will have a more precise definition of what you want. For example, a spreadsheet formula might be a literal number or a cell reference. For such things, you can write rules to match what your application needs and is documented to accept.

—John

Update:fixed typo in substr, reported by dga. Yea, I typed it without checking perlfunc, and I rarely use substr in real code.

Comment on Re: Checking whether a $var is a number Download Code

Replies are listed 'Best First'.
Re: Re: Checking whether a $var is a number by George_Sherston (Vicar) on Sep 05, 2001 at 01:37 UTC
Yes. That (together with a `\|\| $x==1 && substr($x,1,1) ne '1'`) does exactly what I find myself wanting nine times out of ten. That is, what `isNaN` does in js. I'd find it useful to have a built in function, and maybe we're going to get one. § George Sherston	[reply] [d/l] [select]
Re: Re: Re: Checking whether a $var is a number by John M. Dlugosz (Monsignor) on Sep 05, 2001 at 02:39 UTC
Hmm, when does a scalar convert to 1 when it's not a number? Note that I didn't mention that you should already know that the value is "a string" rather than a reference or funky blessed overloaded object, but carefully worded it because I had that in mind.	[reply]
Re: Re: Checking whether a $var is a number by dga (Hermit) on Sep 05, 2001 at 22:59 UTC
I think you have a typo in your substr which should be `substr($x,0,1);` [download] Otherwise the case $x=0; falls into the not a number part of the if.	[reply] [d/l]


We don't bite newbies here... much
	PerlMonks