![]() |
|
Do you know where your variables are? | |
PerlMonks |
Re: passing an array without a name to pop()by The_Dj (Sexton) |
on Dec 04, 2019 at 06:45 UTC ( #11109647=note: print w/replies, xml ) | Need Help?? |
Having a look at the forest with all those trees in the way... Functionally, pop does 2 things: 1] removes the last element from an array and 2] returns that last element (for you to do things with) Passing a literal array rather than a named variable means that the balance of the array is lost to the great bit-bucket in the sky immediately. That means that the effect 1] above is lost. That means that all you are really doing is 2] - getting the last entry in a list. and that is very easily: or (Well, hard-coded like this, you may as well just grab the '9' and be done, but let's pretend this is auto-generated in an eval or something.) HTH
In Section
Seekers of Perl Wisdom
|
|