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checking mysql rows continuously

by bigup401 (Pilgrim)
on Dec 08, 2020 at 11:31 UTC ( [id://11124823]=perlquestion: print w/replies, xml ) Need Help??

bigup401 has asked for the wisdom of the Perl Monks concerning the following question:

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Re: checking mysql rows continuously
by LanX (Saint) on Dec 08, 2020 at 11:49 UTC
    these are mostly SQL questions, not Perl.

    Well ... to get you started with DBI

    > then how can i run the query continuously

    ->fetchrow ° will give you row after row if you don't LIMIT you can run it in a loop

    > skip to next row if the previous one status eq to no

    • either you select status too and decide in Perl to go to the next loop iteration
    • or if no action is needed you insert a where clause WHERE status == "yes"

    I recommend you use DBI#fetchrow_hashref

    Fetches the next row of data and returns it as a reference to a hash containing field name and field value pairs. ...

    If there are no more rows or if an error occurs, then fetchrow_hashref returns an undef

    something like

    my $query = $dbh->prepare("SELECT * FROM items ORDER BY created ASC"); + $query->execute(); while ( my $h_fields = $query->fetchrow_hashref() ) { next if $h_fields->{status} eq 'no'; # not needed w +ith WHERE clause ... }

    (untested)

    Please see SQL tutorials

    UPDATE

    °) uhm ... DBI has no fetchrow! But ...

    $ary_ref = $sth->fetchrow_arrayref; $ary_ref = $sth->fetch; # alias

    down-voted for showing wrong code. (Again)

    Cheers Rolf
    (addicted to the Perl Programming Language :)
    Wikisyntax for the Monastery

      thanks for your response, am going to try it now

Re: checking mysql rows continuously
by Anonymous Monk on Dec 08, 2020 at 14:03 UTC
    How about something vaguely like this ... an inner-join of a table to itself:

    select A.id from table1 A inner join table1 B on (B.id = A.id - 1) where B.status = 'no' and A.status = 'yes'

    I think that would give you the id's rows where a "yes" answer immediately follows a "no" answer. (It will not give you initial "yes" answers that are not followed by "no," so manually add "id#1" to your list.) Armed with this answer, select the rows with greater-or-equal IDs and walk them until you encounter a "no."

    Although I think that this query will still require "a full table scan," at least it will be the database engine that's doing the heavy lifting.

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