Re: Re: Pattern Finding

Here is something that I believe almost satisfies your requirements (just needs a bit more work which I'm not ready to do at the moment, and its not thoroughly tested). It doesn't do very well without a min and max length for each pattern, so maybe if this was wrapped in a sub which adjusted the min and max to various sizes, and evaluated the results on each pass by some heuristic, it could do fairly well with all of the requirements (and that'll have to wait 'till later):

use warnings;
use strict;

# Min and max length for each pattern
my $min = 2;
my $max = 8;
# Number of patterns
my $num = shift;
# Generate pattern to capture words
my $words = join ('', map {
    "(.{$min,$max})" .
    "(?:" . join( '|', map("\\$_", 1..$_)) . ")*"
} 1..$num);

$_="bookhelloworldhellohellohihellohiworldhihelloworldhihellobookpenbo
+okpenworld";
if (my @pats = /^$words$/) {
 for my $pat (@pats) {
  print "[$pat]\n";
 }
}
stan:~/tmp >./tst 5
[book]
[hello]
[world]
[hi]
[pen]
[download]

Update: Greatly simplified. Wondering if I'm doing someone's homework. Noticed that its very similar to nardo's approach, but cleaner, I think, and slightly different behavior due to the newest problem definition. Great minds think alike :)

Comment on Re: Re: Pattern Finding Download Code

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Re: Re: Re: Pattern Finding by Anonymous Monk on Sep 13, 2001 at 19:15 UTC
Hi, This is one of the classic problem in AI. The problem I posted, is actaully an exercise on segmentation section of the OpenLab on http://www.a-i.com.(You will need to register) I have extended it to some other critera such as 'spaces allowed' to meet more general problems. I tried runrig's solution and it doesn't work when number of patterns is 6, for the condition that one pattern cannot be part of another pattern. I am trying to solve this problem myself also, what I am looking for is good design to begin with. Artist. (My computer doesn't keep the login for more than one page, Please let me know if you know the soltuion).	[reply]
Re: Re: Re: Re: Pattern Finding by runrig (Abbot) on Sep 13, 2001 at 21:12 UTC
for the condition that one pattern cannot be part of another pattern This is the toughest condition, and so I don't think it can be done with a regex, at least not with perl's regex engine (hope someone can prove me wrong :). At every stage of capuring a pattern, you'd have to be able to fail if the longer of the current pattern and each of all past patterns doesn't contain the other. Here's some psuedo perl regex code which, if it worked would accomplish this (hope you get the idea), but I'm using things in the wrong way, the regex engine isn't re-entrant, it uses "$1" instead of "\1" (and in a symbolic reference sort of way), etc, but I though it was interesting nonetheless. It would go right after each pattern caputure in my solution: `join('', map { "(?{(length($$i)>length($$_))$$i !~ /$$_/ \| $$_ !~ /$$i/})" } 1..$_)` [download]	[reply] [d/l]


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