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Re^2: min $#a, $#b > $#b

by ikegami (Patriarch)
on Jan 15, 2016 at 20:29 UTC ( [id://1152894]=note: print w/replies, xml ) Need Help??


in reply to Re: min $#a, $#b > $#b
in thread min $#a, $#b > $#b

Perl $#arr is done with magic:

Only when used as an lvalue.

Workaround: 0+$#a.

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