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Re^2: $var == 1 fails when $var = 1 (lost post)by syphilis (Archbishop) |
on Sep 21, 2018 at 14:55 UTC ( [id://1222803]=note: print w/replies, xml ) | Need Help?? |
Well once again Why ? Does that link actually answer either of the 2 issues raised by the OP ? Those 2 issues can be paraphrased as: 1) Why does perl assert that $x is 1 when $x != 1 ? 2) How is it that $x+$y+$z != $x+$z+$y ? Cheers, Rob
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