http://qs1969.pair.com?node_id=122607

lo_tech has asked for the wisdom of the Perl Monks concerning the following question:

Could anyone explain this to me?

Here's the code:

#!/usr/bin/perl -Tw use strict; print $#ARGV; die "where are those args again?\n" unless ($#ARGV > 0); exit;

Here's the output without an @ARGV:

where are those args again?<br> -1

Here's the question:
Why is the print after the die?