lo_tech has asked for the wisdom of the Perl Monks concerning the following question:
Could anyone explain this to me?
Here's the code:
#!/usr/bin/perl -Tw use strict; print $#ARGV; die "where are those args again?\n" unless ($#ARGV > 0); exit;
Here's the output without an @ARGV:
where are those args again?<br> -1
Here's the question:
Why is the print after the die?
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