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prob keeping my floats floating

by perl-diddler (Chaplain)
on Feb 15, 2019 at 01:48 UTC ( [id://1229926]=perlquestion: print w/replies, xml ) Need Help??

perl-diddler has asked for the wisdom of the Perl Monks concerning the following question:

Having a problem keeping my floating point vars as floats and not being truncated to integers when I try to split the string Lemme show working vs. non: 

#working:
>perl -e 'printf "(%s)\n", $ARGV[0]', 2.3
(2.3)

#still good:
> perl -e 'printf "%s\n", do { $ARGV[0] }', 2.3
(2.3)

# now to split 
> perl -we 'printf("(%s)\n", split(q(.), "$ARGV[0]" )  );' 2.3
Missing argument in printf at -e line 1.
()

[download]
Why?

Why missing (argument), and why empty output?
split should output an array in list context and the list length in scalar context, so either a list (array ref, I guess?) of "2, 3" or a scalar '2', as number of elements, no?

What's tripping things up? Ideas?

Replies are listed 'Best First'.
Re: prob keeping my floats floating
by pryrt (Abbot) on Feb 15, 2019 at 02:15 UTC

    split expects a pattern; . is special to a pattern:

    C:\Users\Peter>perl -we "print join ':', split('.', '2.3.4')"

C:\Users\Peter>perl -we "print join ':', split('\.', '2.3.4')"
2:3:4

    [download]

    addendum: showing number of elements:

    C:\Users\Peter>perl -we "print scalar split('.', '2.3.4', -1)"
6
C:\Users\Peter>perl -we "print scalar split('\.', '2.3.4', -1)"
3

    [download]
[reply]
[d/l]
[select]
      Yeah, I thought I had a backslash before it. I fixed it a different way by changing the 1st arg to an explicit pattern: (this one shows the array ref): 
      > perl -we '    
use P;
my @x = split( m{\.}, "$ARGV[0]");
P "\nargv0=%s", "$ARGV[0]";
P "(%s)\n", \@x' "2.3"

argv0=2.3
([2, 3])

      [download]
      Thanks!
[reply]
[d/l]

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