I think you may be a little confused.

$ARGV[0]=$d;
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This overwrites the first command line argument with the value of $d - which is undefined.

shift=$d;
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This doesn't even compile.

"The first rule of Perl club is you do not talk about Perl club."
-- Chip Salzenberg

I was a lot confused

#!/usr/local/bin/perl -w
use strict;

my $d;
$d = shift; #this wiill work
print "$d\n"; #will print argument
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OR


#!/usr/local/bin/perl -w
use strict;

die "argument required\n" unless defined $ARGV[0]; # will stop the scr
+ipt if there is no argument
print "This is what I ment $ARGV[0]\n";
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I screwed that one up good. This is better and tested
learning too monk2b