### Re: Birthday Chances

by ehdonhon (Curate)
 on Feb 15, 2002 at 23:17 UTC ( #145788=note: print w/replies, xml ) Need Help??

The question here is: What are the chances of any n people not having unique birthdays? That's a difficult question. But the cool thing about probability is that you can always find the probability of something by subtracting the probability of its inverse from one. So instead, ask: What are the chances of any n people having unique birthdays? That would be:

(1/365) * ( 1/365 -1) * (1 /365 -2 ) * ... ( 1/365 - (n-1))

And once you have that, the answer to the original question is:

1 - ( (1/365) * ( 1/365 - 1 ) * ( 1/365 - 2) * ... ( 1/365 - (n-1)))

Now just plug in different values of n to find the odds of n people not having unique birthdays.

Replies are listed 'Best First'.
Re: Re: Birthday Chances
by Merlin42 (Friar) on Feb 18, 2002 at 14:36 UTC
I think what you really want is:
1 - ( 1/365 * 1/(365 - 1) * 1/(365 - 2) * ... * 1/(365 - (n-1)) )

Kevin

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