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Re: Re: multi line matching problem

by welchavw (Pilgrim)
on Dec 16, 2003 at 02:50 UTC ( #314956=note: print w/replies, xml ) Need Help??

in reply to Re: multi line matching problem
in thread multi line matching problem

Part of your explanation is flatly erroneous. That \s+ is still greedy. The \n is never matched in your s/\s+|\n/ regex.

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Re: Re: Re: multi line matching problem
by SquireJames (Monk) on Dec 16, 2003 at 02:57 UTC
    For the record, this is the testing that I did, which works fine by me.
    $data = "15 65\n35 6\n445 34,546 59034584\n54 3,450 805;5409 + 8534\n\nStuff..."; print ($data); print ("\nChainging now\n\n"); $data =~ s/\s+|\n/ /g; print ($data);
    Sorry if I misunderstood the question, and I'll take the hit on the greedy statement, perhaps I should have said greedy only for space characters, which is what is wanted....

      Greediness is often misunderstood, but actually that is beside the point considering the regex supplied. After all, what are you saying when you say s/\s+|\n/ /g? Consider...

      $data = "\n\n\n"; $data =~ s/\s+/foobar/g; print "data=>$data\n";

      This outputs "foobar", because \n is whitespace covered by \s.

      Both * and + are greedy operators when not flipped to non-greedy by the application of ?. True, the implications of greediness are very important when greedy operators are combined with alternation (as above), but those implications do not come into play given the example. In the given regex, if you used ? to change your greedy + operator to non-greedy, then the RHS of the alternation operation would be applied. Regardless, the effect would be the same (' ' would be substituted for \n versus for \s, but you'd see the same result). Update: Let me strike that last bit. Got effect of ? on alternation messed up. Rest of explanation is fine (I think).

      Forgive me if I am missing something (I have the feeling I must be).

      On another note (to the original author of the SOPW node), please note that you don't need multi-line matching here. The m and s regex modifiers only have to do with "^", "$", and ".", not with \s.

        Yeah, I didn't realise that \s was a whitespace (as opposed to a plain old space) matcher, hence the use of \s+\n.

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