RE: Re: Date format question

Try:

  printf("%4d.%02d.%02d\n",$year+1900,$month,$day);
[download]

That is, if you don't want today's date to be printed as 100.09.11

You might want to use sprintf if you are trying to get it in a string.

Comment on RE: Re: Date format question Download Code

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RE: RE: Re: Date format question by myocom (Deacon) on Sep 12, 2000 at 03:22 UTC
Actually, you'll also want to use `$month+1`... `printf("%4d.%02d.%02d\n",$year+1900,$month+1,$day);`	[reply] [d/l] [select]


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