Well, I dont know if this counts as a golf question, but considering
BooK's obfus
Huffman encoder i thought maybe people would find this interesting.
Ok to steal a useful diagram from BooKs explaination of Huffman encoding we have the following tree:
The Huffman algorithm pairs the sub-trees by weight. As long as there
+are more than one sub-tree, pairs the lightest two into one sub-tree.
+ I chose to have the lightest branches on the left (bit 0).
49 For a file containing: 27 A
/\ 15 B
22 A 3 C
/\ 1 D
7 B 1 E
/\ 1 F
C 4 1 G
/\
2 2 the resulting tree is (with the weight of eac
+h
/\ /\ sub-tree noted at its root) drawn on the left
+.
D EF G
If we assume a left branch represents a 0 then for D we have 00100. What we want to do is to end up with a tree that has the same properties as a huffman tree, but with its branches organised so that D would be 00000.
More specifically we want to produce a tree so that a depth first left iteration over the leafs gives us the elements ordered from least frequent to most frequent.
This type of ordering would conver the huffmann tree into the following:
49 For alphabet and: 27 A
/\ and weights as so: 15 B
22 A 3 C
/\ 1 D
7 B 1 E
/\ 1 F
4 C 1 G
/\
2 2 Ordered so that the most frequent
/\ /\ have the least 0's in their path
D EF G
A=1 C=001 E=00001 G=00011
B=01 D=00000 F=00010
In this case the change is trivial, a swap of one node. But for larger alphabets and more evenly distributed weights it is not so.
The challenge then is to create a program that fixes a huffmann tree. The input should be a list of symbols weights and paths from a huffman encoder and the ouptut a similer list but adjusted as stated ealier.
Input can be matched with the regex /^\s*(\w+)\s+(\d+)\s+([01]+)\s*$/ where $1 is the symbol, $2 is the weight of the symbol and $3 is the path (in 1's and 0's) in the huffman tree.
a 27 1
b 15 01
c 3 000
d 1 00100
e 1 00101
f 1 00110
g 1 00111
Would produce
a 27 1
b 15 01
c 3 001
d 1 00000
e 1 00001
f 1 00010
g 1 00011
I have implemented a solution to this but I will hold out on posting it till I see some replies. Bonus points if you can figure out a way to build the tree properly *without* using the path information provided, merely the weights.
UPDATE
A little tip: Sometimes you miss the forest for the trees.
Yves
--
You are not ready to use symrefs unless you already know why they are bad. -- tadmc (CLPM)
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