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The function to generate all binary numbers was shown in the solution to the Perl Weakly Challenge 049. Iterate its results and use tr to count the occurrences of ones:
#!/usr/bin/perl use warnings; use strict; use feature qw{ say }; sub increment { my $pos = rindex $_[0], 0; if ($pos > -1) { substr $_[0], $pos, 1, '1'; substr $_[0], $pos + 1, length($_[0]) - $pos - 1, '0' x (length($_[0]) - $pos - 1); } else { $_[0] = '1' . ('0' x length $_[0]); } } my $ones = 3; my $length = 10; my $n = '0' x $length; while ($length == length $n) { increment($n); next unless $ones == $n =~ tr/1//; say $n; }

map{substr$_->[0],$_->[1]||0,1}[\*||{},3],[[]],[ref qr-1,-,-1],[{}],[sub{}^*ARGV,3]

In reply to Re: Generate all unique combinations of 1 and 0 using specified length of "0"-string and count of 1's by choroba
in thread Generate all unique combinations of 1 and 0 using specified length of "0"-string and count of 1's by Lana

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