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There are two uses for '...' - as:
And so... I don't understand why '...; print 1;' exits after ellipsis and not proceeds to print (v5.28). Can someone explain? The sequence ...; print 1; does not proceed to print, because it dies before the print, just at the ...; I understand why 'print ...' breaks: because it makes syntax error. Yes. Because it is not a statement on its own, it is interpreted as the infix range operator, which lacks arguments - so "syntax error".
perl -le'print map{pack c,($-++?1:13)+ord}split//,ESEL'
In reply to Re: Question about ellipsis statement '...'
by shmem
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