![]() |
|
Clear questions and runnable code get the best and fastest answer |
|
PerlMonks |
comment on |
( #3333=superdoc: print w/replies, xml ) | Need Help?? |
Thanks for asking! (but I bet you're sorry you did) You're not wrong there :) :) Its situations like this where MathML or equivalent would be really nice, since you could just give me the forumlae :) In essence, what I understood was the following: For every permutation 1->n check every permutation 1->n to see if it is equivalent according to the rules. If it is, mark it as such. Results: a set of groups of permutations who are deemed equivalent. Are the rules transitive? My head generated psuedocode something like this (no efficiency or anything, just a general algorithm):
But that only works if the rules are both transitive and symmetric (you hint that they are but I may be reading it wrong) I would be interested in the contents of the rules 1->3 if they're not going to make my head ache :)
In reply to Re: Re: Big Picture
by PhiRatE
|
|