/\A 111
[.] 255
[.] ( \d | [1234]\d | 5[012345] )
[.] ( \d | [1234]\d | 5[012345] )
\z/x;
...should work ( with /x modifier used to enhance readability ), but if you're not limited to a regexp, a cleaner ( and more easily reusable!) solution would be something like...
return 1 if
/\A 111 [.] 255 [.] (\d+) [.] (\d+) \z/x
&& $1 <= 55
&& $2 <= 55;
--k.
Update: Fixed typo; thanks CS!
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