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Using a delayed execution assertion, typically used to create recursively matching regexes, I came up with this:
my $re; $re = qr/((.)(??{ $re })\2|.)/; my $s = 'abcdegedfc'; foreach my $i (0 .. length($s) - 1) { local $\ = "\n"; # add newline to print substr($s, $i) =~ /^$re/ and print $1; }
I need a loop, because the regex by itself doesn't search for the longest palindrome, so I added a /^/ anchor to avoid any potential, useless backtacking. It doesn't actually chnage the result.

This little program prints:

a
b
c
deged
ege
g
e
d
f
c
So all you still have to do, is keep the longest match from the loops.

update: I found a second working regex, inspired by holli who came up with the idea to use reverse:

my $s = 'abcdegedfc'; foreach my $i (0 .. length($s) - 1) { local $\ = "\n"; # add newline to print substr($s, $i) =~ /((.*).?(??{ quotemeta reverse $2 }))/ and print $1; }
Output is identical to the previous program.

In reply to Re: Try this in Regexp palindrome by bart
in thread Try this in Regexp palindrome by Anonymous Monk

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