the solution presented by kyle is somehow idiomatic, this would be a good choice. You can use an alternative form w/regular expressions in order to solve a more complicated pattern problem.
The regex-form of kyle's solution would be like:
...
my @Names = qw'A B C';
my @FullRecord = qw'A_1 D_4 C_3 F_6 B_2';
# prepare temporary dictionary
my %h; @h{@Names} = ();
my @DesiredRecord =
grep exists $h{ [/^([^_]+)/]->[0] },
@FullRecord;
print "@DesiredRecord\n";
...
Regards
mwa
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