Hi monks!
I have written a web app that I want to be able to upload pics into ldap. Gif's work just fine, but jpeg's aren't. Apache log says: "gd-jpeg: JPEG library reports unrecoverable error: Not a JPEG file: starts with 0x47 0x3a". I used File::Type to test the data type and for both gif's & jpeg's, it returns "application/octet-stream". I'm assuming the gif library can handle "application/octet-stream", but the jpeg lib can't??? Is there a way I can get this to work for both jpegs & gif's or am I going with the wrong approach?
sub uploadPhoto{
my $self = shift;
my $q = $self->query;
my $admin=($self->session->param('membership') =~ /$Intranet::
+Web::CONFIG{securityldapsuper}/);
my $jpegimg='';
my $photo = $q->upload('photo');
my $dn=$q->param('dn');
if($photo && $admin && $dn){
binmode($photo);
my $ft = File::Type->new();
# return "type=".$ft->checktype_contents($photo); #used
+ for testing
my $image = GD::Image->newFromGif($photo);
unless($image){$image = GD::Image->newFromJpegData($ph
+oto);#tried this and newFromJpeg with the same result
unless($image){return "Not a valid gif or jpeg file.";
+}}
$jpegimg=$image->jpeg();
undef $image;
unless($jpegimg){return "Problem uploading image.";}
my $ldap=Net::LDAP->new($Intranet::Web::CONFIG{ldaphos
+t}) or die "error connecting to LDAP $Intranet::Web::CONFIG{ldaphost}
+: $@\n";
my $mesg=$ldap->bind($Intranet::Web::CONFIG{ldapuser},
+ password=>$Intranet::Web::CONFIG{ldappassword}) or die "error bindin
+g: $@\n";
if($jpegimg){
my $mesg1=$ldap->modify($dn,replace=>{jpegPhot
+o=> $jpegimg,thumbnailPhoto=>$jpegimg, });
$mesg1->code && die $mesg1->error;
}
$ldap->unbind;
}
return "Photo uploaded".(length($jpegimg));
}
and my html:
<form name='photoForm' action='[% userbase %]/ldap.pl' enctype="multip
+art/form-data" method='post' id='photoForm'>
<input type="hidden" name="rm" value="getDetailUser">
<input type="hidden" name="upload" value="0">
<input type="hidden" name="dn" value="[% user.dn %]">
<input type="file" name='photo'> <input type="button" value='Upl
+oad' onclick='this.form.upload.value=1;this.form.submit();'>
</form>
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