![]() |
|
No such thing as a small change | |
PerlMonks |
comment on |
( #3333=superdoc: print w/replies, xml ) | Need Help?? |
Hi,
By types and tokens i meant, if i have a word "the" multiple times in a array i need to process it as many times as it is in the array. But in hash it avoids duplicates by having the token of each word. if a word "the" appears six times in a hash. then type of "the" is only one. but the token of "the" is 6.. Is it correct what i m speaking In reply to Re^2: hash to differentiate type and tokens
by sarvan
|
|