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It's funny that when people "tackle" the Monty Hall problem with a program, they tend to write one that uses a simulation, running thousands (if not more) of test runs. And that while it's easy to brute-force it, as there are at most 108 cases to examine (3 places for the main prices, 3 initial picks, 2 possible doors for Monty to pick, switch/not-switch).
use 5.010; my @doors = (1 .. 3); my $switch_wins = 0; my $switch_losses = 0; my $noswitch_wins = 0; my $noswitch_losses = 0; # # Place a price # foreach my $price (@doors) { # # Pick a door # foreach my $pick (@doors) { # # Monty's pick # my @monty_choices = grep {$_ != $price && $_ != $pick} @doors; foreach my $monty_pick (@monty_choices) { # # Switch or not? # foreach my $switch (0, 1) { # # If switching, find final door # my $final_pick; if ($switch) { ($final_pick) = grep {$_ != $pick && $_ != $monty_pick} @doors; } else { $final_pick = $pick; } my $prob = 1 / @monty_choices; if ($switch) { $switch_wins += $prob if $final_pick == $price; $switch_losses += $prob if $final_pick != $price; } else { $noswitch_wins += $prob if $final_pick == $price; $noswitch_losses += $prob if $final_pick != $price +; } } } } } printf "Switching: win percentage = %.2f%%\n", 100 * $switch_wins / ($switch_wins + $switch_losses); printf "No switching: win percentage = %.2f%%\n", 100 * $noswitch_wins / ($noswitch_wins + $noswitch_losses); __END__ Switching: win percentage = 66.67% No switching: win percentage = 33.33%

In reply to Re: Holiday parcel puzzle by JavaFan
in thread Holiday parcel puzzle by cavac

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