Re^4: RFC: A Perlesque Introduction to Haskell, Part One (draft)


The stupid question is the question not asked
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by Sidhekin (Priest)

on Jun 24, 2004 at 02:29 UTC ( [id://369227]=note: print w/replies, xml )

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Haskel goes a little further, though, because it supports function-dispatch by pattern matching...

My mind has been full of Perl6 lately ... so bear with me ...

multi sub factorial (Any where {$^n==0} $n) { 1 }
multi sub factorial ($n) { $n * factorial $n-1 }
[download]

... which of course will recurse infinitely when given factorial 0.5 or factorial -1 ...

ObTopic: How do the Haskell examples handle those cases?

print "Just another Perl ${\(trickster and hacker)},"
The Sidhekin proves Sidhe did it!

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Re^5: RFC: A Perlesque Introduction to Haskell, Part One (draft) by ihb (Deacon) on Jun 24, 2004 at 02:44 UTC
How do the Haskell examples handle those cases? It doesn't. You can use "boolean guards" though to handle different cases: `fac 0 = 1; fac n \| n > 0 = n * fac (n-1) \| otherwise = ...` [download] otherwise is just a standard alias for `True` to make it read well. `ihb`	[reply] [d/l] [select]
Re^5: RFC: A Perlesque Introduction to Haskell, Part One (draft) by etcshadow (Priest) on Jun 24, 2004 at 02:40 UTC
Touche. I was referring to perl 5, not perl 6. But that's cool to know. `------------ :Wq Not an editor command: Wq` [download]	[reply] [d/l]

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