http://qs1969.pair.com?node_id=41313


in reply to Re: Boolean algebra
in thread Boolean algebra

Maybe I wasn't clear. This means that
(abc)(b-ac)
and
(cb-a)(bca)
are equally correct input strings (they are even the same expression since (a AND b AND c) OR (b AND NOT a AND c) is the same as (c AND b AND NOT a) OR (b AND c AND a)).

But the output of the first reduction would be

(bc)
and of the second reduction
(cb)


Of course there can be many negated variables like this:
(-a-b-c-d)(-c-da-b)
which would result in
(-b-c-d)