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Re^2: Integer overflow questionby waswas-fng (Curate) |
on Jan 03, 2005 at 00:23 UTC ( [id://418845]=note: print w/replies, xml ) | Need Help?? |
Another thing you may want to mention about bigint is that it is slower than incrementing a normal int. This may be a limiting factor in a counter that is used in a very tight loop (requirement that it support very large ints could mean tight loop or long run).
-Waswas
In Section
Seekers of Perl Wisdom
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