This snippet shows how to use an expression as an lvalue. It's based on something my boss said you could only do in Algol68.
($a,$b) = (0,1); ($a < $b ? $a : $b) = $a+$b for (1..$n); print $n%2 ? $a : $b, "\n"
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Re: Fibonacci numbers with lvalues
by Adam (Vicar) on Dec 01, 2000 at 07:11 UTC |
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Cool Uses for Perl