http://qs1969.pair.com?node_id=545486

wannabeperlie has asked for the wisdom of the Perl Monks concerning the following question:

Hi,

I have a question regarding delaying interpolation of a variable when it is used in a regular expression. The below code snippet demonstrates the problem

%cat test.pl

#!/usr/bin/perl use strict; my $line = "System has tool zigzag version 3.6"; my $match = 'System\s+has\s+tool\s+([0-9a-zA-Z_-]+)\s+version\s+(.*)'; my $replace = 'System has tool $1 version ABC'; $line =~ s/$match/$replace/g; print "Line after replacement: $line \n";
When I execute the above code the output I get is :

%./test.pl

Line after replacement: System has tool $1 version ABC

The output I need is :

Line after replacement: System has tool zigzag version ABC

How do I get $1 to be interpolated in the replacement pattern ? I tried other variants like : e,ee etc but none yeild the result I need.