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Re^2: qx and $!by blazar (Canon) |
on Oct 18, 2006 at 16:19 UTC ( [id://579127]=note: print w/replies, xml ) | Need Help?? |
Update: Hey, no fair davorg! You clearly have the perldocs memorized, whereas I had to go look it up; that's why you beat my answer! :) It's not fair only if you assume that there's a competition going on, at who answers the first - although I admit I like to be the one myself, on occasions. Otherwise, repetita iuvant. (Latin idiomatic expression which means "repetitions help".) Well, if taken in non excessive doses, cum grano salis...
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