Re: Undocumented Operator Japh

Here's a crack at deobfuscating it:

First things first, fix that pesky whitespace.

@= = "GqwpWrlplbnTbnpDwghav" =~ /.../g;
@+ - map { +map ++$_, @= } + $=  ... 3**7;
@' = split /(?=[A-Q])/, join $*, @=;
die +qq+ @'$/+
[download]

Clean up a few things, simplifying where possible:

@= = "GqwpWrlplbnTbnpDwghav" =~ /.../g;
@+ - map { map ++$_, @= } + 60  ... 2187;
@' = split /(?=[A-Q])/, join $*, @=;
die qq" @'$/"
[download]

But there's still those extra "+"'s and "-"'s in that second line... Well, thanks to that hint about blazar's post, I think I know what's going on, so let me try something...

for( qw( Gqw pWr lpl bnT bnp Dwg hav ) ){
  my $num = $_;
  #for( 60 ... 2187 ){ $num = ++$num }
  # the above changed to the below to "deobfuscate" the deobfuscation.
  for( 60 .. 2187 ){
    $num++;
  }
  push( @array, $num );
}
print "$_\n" for @array;

OUTPUT:
Jus
tAn
oth
erP
erl
Hac
ker
[download]

Success!

So here's what's going on: line 1 sets the @= array to some values, which happen to be the equivalent of "( 'Gqw', 'pWr', 'lpl', 'bnT', 'bnp', 'Dwg', 'hav' )".

Line 2 cleverly "re-maps" (using a map inside a map, nonetheless) the @= array by ++ "incrementing" every value 2,127 times - the exact number of times required to "increment" Gqw to Jus^*. The preceeding @+ - just adds a little line noise, as it doesn't seem to affect the final result if removed. Same with the + in front of $= (which, incidentally, (as documented ;) defaults to 60).

Line 3 joins @= by the value of $*, which is (as documented ;) undefined, giving us "JustAnotherPerlHacker", which is then split in between a lowercase character and a following uppercase character thanks to the zero width positive look-ahead assertion /(?=[A-Q])/, and the resulting list from the split is stored in @'.

Finally, with a few + cluttering things up (and used as qq's quoting character for interpolating the values of the variables in the string given to die), you 'print' the contents of @', trusting that (as documented ;) the default value of a single space for $" hasn't changed, and $/ also defaults (as documented ;) to a newline.

^* (The bit of perldoc perlop that details this is: The auto-increment operator has a little extra builtin magic to it. ... If, however, the variable has been used in only string contexts since it was set, and has a value that is not the empty string and matches the pattern "/^[a-zA-Z]*[0-9]*\z/", the increment is done as a string, preserving each character within its range, with carry .... Incrementing "Gqw", and you get "Gqx")

Update: Cleared up the "obfuscated deobfuscation" as noted by ysth, though the original test was written to most closely resemble (from at least my point of view) the original obfuscated code. Apologies for any confusion. Also added a little extra explanation (with reference to associated documentation).

--chargrill

s**lil*;  $*=join'',sort split q**;  s;.*;grr; &&s+(.(.)).+$2$1+; $; =
qq-$_-;s,.*,ahc,;$,.=chop for split q,,,reverse;print for($,,$;,$*,$/)
[download]

Comment on Re: Undocumented Operator Japh Select or Download Code

Replies are listed 'Best First'.
Re^2: Undocumented Operator Japh by liverpole (Monsignor) on Nov 22, 2006 at 12:59 UTC
Nicely done, chargrill, as always++ One of the fun parts of creating the obfuscation was writing the subroutine to "decrement" a word (eg. "Jus"-- => "Jur"). It wasn't clear initially clear how many "increments" I was going to want to make, and if it turned out to be more than a few (as it certainly did), I needed to a subroutine to do it. This was what I ended up with: `sub decrement_word { my ($pword) = @_; my @vals = map { ord $_ } (split //, $$pword); my $idx = $#vals; while (1) { if ($vals[$idx] != ord('a') and $vals[$idx] != ord('A')) { --$vals[$idx]; last; } if (0 == $idx) { shift @vals; last; } $vals[$idx] += 25; --$idx; } my $word = join '', map { chr } @vals; $$pword = $word; }` [download] It's too bad, I think, that a word "decrement" isn't part of the Perl language, at least for the obfuscatory potential it would provide. ;-) s''(q.S:$/9=(T1';s;(..)(..);$..=substr+crypt($1,$2),2,3;eg;print$..$/	[reply] [d/l]
Re^2: Undocumented Operator Japh by ysth (Canon) on Nov 22, 2006 at 01:09 UTC
`for( 60 ... 2187 ){ $num = ++$num }` Please don't obfuscate your deobfuscation.	[reply] [d/l]


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