Hi rsmah++,
That is a very interesting question!
I don't know if this is the best answer, but my first thought was to try assigning to the variable and see what happens:
use strict;
use warnings;
my $a = "123";
foo($a, "456");
sub foo {
for (my $i = 0; $i < @_; $i++) {
my $type = eval { $_[$i] = "variable" } || "constant";
printf "Arg #%d is $type\n", $i + 1;
}
}
The output of this is:
Arg #1 is variable
Arg #2 is constant
Since the write operation is wrapped in an eval, it returns undef if the assignment failed (constant), otherwise the result of the assignment.
s''(q.S:$/9=(T1';s;(..)(..);$..=substr+crypt($1,$2),2,3;eg;print$..$/
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