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Re: Why the error?

by merlyn (Sage)
on Mar 10, 2001 at 03:29 UTC ( #63399=note: print w/replies, xml ) Need Help??

in reply to Why the error?

it means what it says. that's the wrong syntax. use
instead. Also, you should probably actually return a value somewhere, so that the CGI transaction is complete.

-- Randal L. Schwartz, Perl hacker

Replies are listed 'Best First'.
Re: Re: Why the error?
by SilverB1rd (Scribe) on Mar 10, 2001 at 03:53 UTC
    Thanks merlyn, that fixed it.
    <Warning>I'm new</Warning> what does the \* do?
    That is how they showed it in the CGI info page.

    The Price of Freedom is Eternal Vigilance
      In this instance, the "\*" basically returns a pointer to the filehandle. Something to do with typeglobs, an area I haven't explored much (yet). The asterisk indicates the typeglob (I believe), and the backslash performs it's usual "return-a-reference-to-this" function.

      A typeglob is basically a complete symbol table entry, but you can use them (and references to them) like file handles.

      Hot Pastrami
      \* is called a typeglob... if you are a beginner, this is way advanced for you to understand..
      in some words, this is a reference (and here a reference to a filehandle)
      the * is the typeglob.
      and the \ is to dereference it.
      a typeglob references anything from a $scalar, to an @array on to a FILEHANDLE
        Ummm... * is a typeglob, which means in a way "Everything named ...". So *foo is everything named foo: $foo,@foo,%foo,&foo,the fh foo, and the format foo,(I'm sure I missed something,,but don't know what.) \*foo is a reference to the typeglob. A typeglob or a ref to it, can be used as an "indirect filehandle". Typeglobs are also used to create aliases:
        *foo=*bar; #Now everything named bar is also named foo *fooo=\$barr #now $fooo is an alias to $barr
        And to create a refernce using the *foo{THING} thing which is explained in perlref(As the 7th way to create a reference). For more about typeglobs, read perldata.

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