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Re: Re: Regular Expression Question

by larryk (Friar)
on Mar 27, 2001 at 22:00 UTC ( #67562=note: print w/replies, xml ) Need Help??

in reply to Re: Regular Expression Question
in thread Regular Expression Question

you are right to suspect that this would not work - the single \d as opposed to \d+ before the % would mean that the regex would fail to match unless the % was between 0 and 9.

what I expect you are looking for is for(<>) { /(\d+)%/; print if $1 >= 88 }

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Re: Re: Re: Regular Expression Question
by SilverB1rd (Scribe) on Mar 27, 2001 at 23:29 UTC
    Thanks larry. Typo on my part. It was supposed to be (\d+)%

    The Price of Freedom is Eternal Vigilance

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