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Re: About this behaviorby Macphisto (Hermit) |
on Apr 16, 2001 at 05:45 UTC ( [id://72738]=note: print w/replies, xml ) | Need Help?? |
Well, and someone please correct me if I mislead on this post, If you think about the code: foreach $each (@list) { $each *= 2; $newlist$i = $each; ++$i; } From Programming Perl: Note that the loop variable becomes a reference to the element itself, rather than a copy of the element. Hence, modifying the loop variable will modify the original array. The snippet loops through the contents of @list and as each cell gets looked at, it is assigned to $each. $each is then modified by multiplying by 2. Modifying $each, modifies the value in the shell, due to the way foreach is constructed in perl. I believe that is all correct. If I have made any mistakes ( other than grammar, and spelling ), someone please tell me. Macphisto the I.T. Ninja Everyone has their demons....
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