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Re: Space character when using push function on arraysby nvivek (Vicar) |
| on Jul 15, 2010 at 12:13 UTC ( [id://849764]=note: print w/replies, xml ) | Need Help?? |
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You're getting that output because the value $" by default is space.That's why,you're getting 0\n then space which $" is a delimiter and then 1\n followed by space and it continues. If you want to check it,you change the value of $" and check it.You'll understand.To know better about these kind of special variables you refer this URL. http://www.tutorialspoint.com/perl/perl_special_variables.htm
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