Re: make subroutine that takes expression as implicit block as first arg

In pure Perl, this isn't possible. However, 5.12 has pluggable keywords; I wouldn't rule it out it's possible by creating a new keyword. Unfortunally, my knowledge about pluggable keywords doesn't extend further than "I know they exist".

Comment on Re: make subroutine that takes expression as implicit block as first arg

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Re^2: make subroutine that takes expression as implicit block as first arg by LanX (Saint) on Aug 14, 2010 at 16:44 UTC
Interesting, looks like how I imagine Devel::Declare might work ... http://perldoc.perl.org/5.12.1/perlapi.html#PL_keyword_plugin but: `NOTE: this function is experimental and may change or be removed without notice.` Cheers Rolf	[reply] [d/l]


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