$ ksh << END_OF_KSH
> perl << END_OF_PERL
> my $foo = qq{ bar \n };
> print qq{ FOO=$foo };
> END_OF_PERL
> END_OF_KSH
$ echo $FOO
$
The astute Shell hackers among us will see a nested set of heredocs. The more astute Shell hackers will say "but
$foo is not escaped, nor is it defined within ksh, so perl sees
'' instead of
$foo." Well, that's what I thought too.
$ echo "$foo"
$ echo "\$foo"
$foo
$ echo << ECHO
$foo
ECHO
$ echo << ECHO
\$foo
ECHO
$ echo << ECHO
\\$foo
ECHO
\
$
So it would seem that the shell escapes things differently within heredocs. How can I get my
$foo's through to perl?
brother dep, shell warrior.
--
Laziness, Impatience, Hubris, and Generosity.