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Re^2: hash comparisonby sarvan (Sexton) |
on Jul 25, 2011 at 07:47 UTC ( #916498=note: print w/replies, xml ) | Need Help?? |
Hi,
Thanks for the reply
And here is the doubt. suppose a word in the candidate that is not at all present in the reference, in such case it gives me the count as 1.(since 1 time it appeared in $cand). But, i expect it to be zero. because it dint appear in $ref.. An Example sentences: $candidate="it is not probable that it is the end"; $reference="it is unlikely that it is the end";
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