|
|
| Think about Loose Coupling | |
| PerlMonks |
Re: Sub ref from string without evalby Khen1950fx (Canon) |
| on Apr 02, 2012 at 15:30 UTC ( #963042=note: print w/ replies, xml ) | Need Help?? |
|
I would convert "Foo" to \&Foo without using an eval by using a closure:
In Section
Seekers of Perl Wisdom
|
|
||||||||||||||||||||