Coming in at a whopping 223(!) characters, a first attempt:
for(0..$#_){if($_[$_]=~/X/){$t+=10+($_[$_+1]=~/X/?10:$_[$_+1])+($_[$_+
+2]=~/X/?10:($_[$_+2]=~/\//?10-$_[$_+1]:$_[$_+2]))}if($_[$_+1]=~/\//){
+$t+=10+($_[$_+2]=~/X/?10:$_[$_+2]);splice@_,$_+1,1;last if!defined$_[
+$_+2]}else{$t+=$_[$_]}}$t
There
has to be a better way... I thought about switching the if-elsif-else to
BLOCK,next if(EXPR);, but I couldn't figure a way to get rid of the
splice in the
elsif block. *shrugs*
Update:
for(0..$#_){if($_[$_]=~/X/){$t+=10+($_[$_+1]=~/X/?10:$_[$_+1])+($_[$_+2]=~/X/?10:($_[$_+2]=~/\//?10-$_[$_+1]:$_[$_+2]));last if!defined$_[$_+3]}if($_[$_+1]=~/\//){$t+=10+($_[$_+2]=~/X/?10:$_[$_+2]);splice@_,$_+1,1;last if!defined$_[$_+2]}else{$t+=$_[$_]}}$t
That fixes the perfect score problem. Comes in at 242.
Update2: With some ideas from chipmunk, I'm down to 208. (I didn't want to steal his concept, but improve my own. *grins*)
@b=@_;sub X{pop=~X?10:pop}while(($_=shift@b)+1){$t+=10+X(($b[0])x2)+X(
+($b[1]=~/\//?10-$b[0]:$b[1]),$b[1])and(defined$b[2]||last)if/X/;if($b
+[0]=~m!/!){$t+=10+X(($b[1])x2)and(defined$b[2]||last)}else{$t+=$_}}$t
------
/me wants to be the brightest bulb in the chandelier!
Vote paco for President!
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