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As shown in the Algorithm::Permute synopsis, if you want r elements out of the n objects in each permutation,
# but also you can create r of n objects permutation generator, where +r <= n my $p = Algorithm::Permute->new([1..4], 3);

A practical example is shown here, where there are n=4 objects and I take groups of r=2:

C:\usr\local\share>perl -MAlgorithm::Permute -e "my $p=Algorithm::Perm +ute::->new([1..4],2); while(my @res=$p->next){print qq(@res\n)}" 2 1 1 2 3 2 2 3 3 1 1 3 4 2 2 4 4 3 3 4 4 1 1 4

Your example would be ...->new([1..8],5) to get permutations of length 5 from the 8 objects given. Or

C:\usr\local\share>perl -MAlgorithm::Permute -e "my $p=Algorithm::Perm +ute::->new([1..8],5); while(my @res=$p->next){print qq(@res\n)}" 5 4 3 2 1 4 5 3 2 1 4 3 5 2 1 4 3 2 5 1 4 3 2 1 5 5 3 4 2 1 3 5 4 2 1 3 4 5 2 1 3 4 2 5 1 3 4 2 1 5 ... 8 1 2 3 4 1 8 2 3 4 1 2 8 3 4 1 2 3 8 4 1 2 3 4 8

In reply to Re: Getting permutations of length n of an array of length greater than n? by pryrt
in thread Getting permutations of length n of an array of length greater than n? by LittleJack

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