It looks perfectly clear to me.
If you're storing a 32 bit integer, on a little endian machine you get
[byte 1][byte 2][byte 3][byte 4]
increasing memory address ->
while on a big endian machine you get
[byte 4][byte 3][byte 2][byte 1]
increasing memory address ->
Obviously, big endian is superior and the only true way to store data in memory ;)
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