That's completely wrong.
1. Closing one end of a pipe doesn't cause close on the other end to return an error.
$ perl -E'
pipe($r, $w) or die $!;
close($w) or die $!;
close($r) or die $!;
2. Closing a pipe created by open(my $fh, '|-', ...) reads the process (calls wait). It's very appropriate to do this, whether the pipe is closed or not. Closing such a handle returns the same thing as system.
$ perl -E'
open(my $fh, "|-", "perl", "-e", "exit 123") or die $!;
die("$!\n") if $? == -1;
die("Signal ".( $? & 0x7F )."\n") if $? & 0x7F;
die("Error ".( $? >> 8 )."\n") if $? >> 8;
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